Question: A program takes 1 0 seconds to run on a machine with a 1 0 MHz clock rate. The same program takes 3 seconds to

A program takes 10 seconds to run on a machine with a 10 MHz clock rate. The same program takes 3 seconds to run on a 20 MHz machine with an identical ISA and a floating point accelerator. If 55% of the time is spend executing floating point instructions on the 10 MHz machine, by how much does the accelerator speedup these instructions?

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