A project involves the activities shown below (activity times, standard deviation sociated with each activity, and Immediate predecesor(s) for each activity are also shown). The data are in weeks As we discussed in the cas, the environment of a project can be either determinate or probabilistic. If it is probabilistle then, according to convention, the analyst is required to give three different time estimates for completing each activity. These time estimates are usually denoted by: (most optimistle time), m (most likely time), and b (most pessimistle time). The expected time for an activity is the weighted average of the three estimates. A welght of 1 is assigned to "2", 4 to "m", and 1 to "b" and the expected time for each activity is then calculated by: +4m + b (1) 6 Further, it is also possible to estimate a standard deviation for each activity as follows: b-a (2) Please keep the above two relationships in mind while answering all questions. ACTIVITY EXPECTED TIME STD, DEVIATION A 12 IMM. PREDECESSOR 1 None B 10 None 8 D 1 E 6 1 c F 18 2 BA 11 1 DE 21 C 1 E,G Nome Q# 4. The number of paths involved in this network is: a) Just 4 b) Just 5 c) Just 6 d) Just 7 D e) None of the above Q5. The maximum path slack in this network is! ) 12 weeks b) 8 weeks c) 10 weeks d) 9 weeks e) None of the above E Q# 6. The length of the critical path in this network is: a) 24 weeks b) 35 weeks c) 32 weeks d) 30 weeks e) None of the above Q# 7. For activity A, the value of "m" -12; and "b" - 15. Then, the most optimistle time" for activity is