al prove lim (4x-5)=7 X+3 if 0...

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al prove lim (4x-5)=7 X+3 ↓ if 0<x-3128, then |(4x-5)-7| <E 14x-5-21=4x-12 = 4/x-31,50 if 0²1x-3128, then 4/x-3/4 E, that is, if ockx-3/8, then Ix-314€ 4 So choose &=& 4 Thus, 02/x-312€ 6-314€ → multiplying all sides by 4, then. 0<4/x-3148 if 0</x-3)<8, then 4| X-31CE. Therefore, lim (4x-5)=7 X-3 HE 7. 7-E /9-S y=4x-5 348 al prove lim (4x-5)=7 X+3 ↓ if 0<x-3128, then |(4x-5)-7| <E 14x-5-21=4x-12 = 4/x-31,50 if 0²1x-3128, then 4/x-3/4 E, that is, if ockx-3/8, then Ix-314€ 4 So choose &=& 4 Thus, 02/x-312€ 6-314€ → multiplying all sides by 4, then. 0<4/x-3148 if 0</x-3)<8, then 4| X-31CE. Therefore, lim (4x-5)=7 X-3 HE 7. 7-E /9-S y=4x-5 348

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Explanation Given 0 choose Then for any x with 0 x 3 6 4... View the full answer