Question: A Python program is running and must open a file name x. out in a subdirectory next 2 of a subdirectory next 1 of

A Python program is running and must open a file name " x. out" in a subdirectory next 2 of a subdirectory next 1 of the current directory (thus, two directories down). Which of the following are portable ways to accomplish this? fh = open ("next1 ext 2\x. out") fh = open ("next1ext2/x.out") import os path = os.path.join ("next1", "next2", "x.out") fh = open (path) import os fh = open (os.path.unixtolocal("next1ext2/x.out")) import os fh = open (os.path.join("next1", "next2", "x", "out"))
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
