Question: A quadratic trial solution within the range x = [ 0 , L ] may be expressed as widehat ( u ) ( x )

A quadratic trial solution within the range x=[0,L] may be expressed as
widehat(u)(x)=N1q(x)hat(u)1+N2q(x)hat(u)2+N3q(x)hat(u)3
where N1q,N2q and N3q are quadratic shape functions defined as
N1q(x)=1-3Lx+2L2x2
N2q(x)=4Lx-4L2x2
N3q(x)=-1Lx+2L2x2
and parameters hat(u)1,hat(u)2 and hat(u)3 are the values of the trial solution hat(u)(x) at x=0,x=L2
and x=L, respectively.
Derive the quadratic shape functions above. The process of derivation is similar to the 2nd
derivation of the linear shape functions shown in class.
A quadratic trial solution within the range x = [

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