A quality analyst wants to construct a sample mean chart for controlling a packaging process She knows from past experience that the process standard deviation is known to be equal to two kilograms Each day last week, he randomly selected four packages and weighed each one The data from that activity appears below Weight Day Package 1 Package 2 Package 3 Package 4 Monday 23 22 23 24 Tuesday 23 21 19 21 Wednesday 20 19 20 21 Thursday 18 19 20 19 Friday 18 20 22 20 Q 1 What is the number of samples k in this problem Please fill in the box below You do not need to show your calculations The answer is k Q 2 Calculate the UCL and the LCL for the X bar chart, using 2 for variations due to natural causes Please fill in the box below You do not need to show your calculations The answer is UCL 22 6 LCL 18 6

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Question: A quality analyst wants to construct a sample mean chart for controlling a packaging process. She knows from past experience that the process standard deviation

A quality analyst wants to construct a sample mean chart for controlling a packaging process. She knows from past experience that the process standard deviation is known to be equal to two kilograms. Each day last week, he randomly selected four packages and weighed each one. The data from that activity appears below.

	Weight
Day	Package 1	Package 2	Package 3	Package 4
Monday	23	22	23	24
Tuesday	23	21	19	21
Wednesday	20	19	20	21
Thursday	18	19	20	19
Friday	18	20	22	20

Q-1: What is the number of samples k in this problem? Please fill in the box below. You do not need to show your calculations.

The answer is: k =

Q-2: Calculate the UCL and the LCL for the X-bar chart, using +-2 for variations due to natural causes. Please fill in the box below. You do not need to show your calculations.

The answer is:

UCL = 22.6

LCL = 18.6

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