Question: A recent newspaper article reported that the average leisure time for males is less than 20 hours per week. A random sample of 30 men

A recent newspaper article reported that the average leisure time for males is less than 20 hours per week. A random sample of 30 men was selected and found to have a mean leisure time of 16.9 hours per week with a standard deviation of 6 hours per week. Use a 5 percent level of significance to test the validity of this claim.

1)State the data type and parameter of interest.

Data type:

Parameter of interest:

2)State the Null and Alternative hypotheses

Ho:

HA:

3)State the test statistic, its distribution and the level of significance. State the required condition

Test statistic:

Distribution of the standardized test statistic:

Level of significance:

Required conditions:

4) State the decision rule (in terms of the p-value):

5) Obtain the p-value (from the appropriate output) and compare with the decision rule:

t-Test of a Mean z-Test of a Mean 16.9 Sample mean Sample standard deviatio Sample size Hypothesized mean Alpha 630 t Stat P

6) Derive your conclusion regarding the claim in the newspaper article report.

t-Test of a Mean z-Test of a Mean Sample mean CSample standard deviatid Sample size Hypothe sized mean Alpha Sample mean Population standard deviation Sample size Hypothesized mean Alpha z Stat P(Z

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