Question: A rectangular conductive loop is placed near a long, straight wire at a distance a carrying an alternating current of I(t) = Io sin(ot). Here,

A rectangular conductive loop is placed near a long, straight wire at a distance a carrying an alternating current of I(t) = Io sin(ωot). Here, ωo =2π/T, T = 0.02 s is the period of the alternating current. Both the wire and the loop are in the same plane. The side lengths of the loop are L1 = a and L2 = 2a, and the resistance R = 20 Ω is connected
between the two open ends of the loop (take ln2 = 0.6 and π = 3)

1(t) a L L www R

19. What is the voltage, in terms of µo, Io and a, between the ends of the resistor at t = T /2?
(a) 12aµoIo 

(b) 50aµoIo 

(c) 180aµoIo 

(d) 60aµoIo 

(e) 6aµoIo

20. What is the current, in terms of µo, Io and a, passing through resistance at t = T /2?
(a) aµoIo 

(b) 9aµoIo

(c) 5aµoIo

(d) 3aµoIo

(e) 4aµoIo
 

1(t) a L L www R

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To find the voltage induced in the loop due to the alternating current in the straight wire well use Faradays Law of electromagnetic induction which s... View full answer

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