Question: A sample is irradiated at its absorption maximum () = 500 nm) max with 1.00 X 1018photons. The absorbance of the sample was found to

A sample is irradiated at its absorption maximum () = 500 nm) max with 1.00 X 1018photons. The absorbance of the sample was found to be 0.680. Calorimetric analysis indicated that 0.100 J of the incident light energy was converted into heat in the sample. What is the approx- max imate value of A' of the fluorescent light, assuming aquantum yield for fluorescence of 1.00? In this context, a quantum yield of 1.00 means that, for every photon absorbed, one photon is fluoresced
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
