A simple pendulum oscillates between $+-6\mathrm{.}0($as measured from the vertical$)$ on the surface of Earth. The length of the pendulum is $0\mathrm{.}50$ m $.$ Define $t_{\text{f}\text{u}\text{l}\text{l}}$ as the amount of time that the pendulum takes to move from $6\mathrm{.}0$ to $5\mathrm{.}0,$ and define $t_{\text{h}\text{a}\text{l}\text{f}}$ as the amount of time that the pendulum takes to move from $3\mathrm{.}0$ to $-3\mathrm{.}0$ during the same swing.

Compare the two times by determining the ratio $\frac{t_{\text{f}\text{u}\text{l}\text{l}}}{t_{\text{h}\text{a}\text{l}\text{f}}}.$

$\frac{t_{\text{f}\text{u}\text{l}\text{l}}}{t_{\text{h}\text{a}\text{l}\text{f}}}=$