A simplified process for making acetaldehyde $(C{H}_3$CHO$)$ from ethylene $(C_2{H}_4)$ is as

follows: $1000$kmo$\frac{l}{s}$ of a fresh feed stream containing $65\%C_2{H}_4,34\mathrm{.}5\%$ oxygen $(O_2)$ and

$0\mathrm{.}5\%$ nitrogen $(N_2)($composition on a mol basis$)$ enters the process at $125C$ and $\frac{3}{b}ar.$ This

feed enters a reactor maintained at $125C$ and $3$ bar in which acetaldehyde is produced

according to the following overall reaction.

$C_2{H}_4+0\mathrm{.}5O_{2}C{H}_3$CHO

Ethylene must be present in excess to avoid forming explosive mixtures so the single pass

molar conversion of ethylene is $30\%.$ The stream leaving the reactor enters a scrubber where

it is mixed with $2000$kmo$\frac{l}{s}$ of water. All of the water and the acetaldehyde leave the

scrubber in the bottoms stream, and all the remaining components leave as an overhead

stream. $20\%($mol basis$)$ of the overhead stream is purged to prevent accumulation of

nitrogen in the system and the remainder is recycled to the reactor. The bottoms stream

leaving the scrubber is sent to a distillation column where a pure acetaldehyde product stream

is recovered. Acetaldehyde has a boiling point of $20\mathrm{.}2C.$

Calculate the:

a$)$ Flowrate of Ethylene just after exiting the reactor. $($ kmo$\frac{l}{sec})$

b$)$ Flowrate of Oxygen$($O$2)$ just after exiting the reactor. $($ kmo$\frac{l}{sec})$

c$)$ Flowrate of Ethylene in recycle stream. $($kmol$/$sec$)$

d$)$ Flowrate of Oxygen$($O$2)$ in recycle stream. $($kmol$/$sec$)$