Question: A singular value decomposition of a matrix AA is as follows: A= .5 .5 .5 .5 .5 .5 -.5 -.5 .5 -.5 -.5 .5 .5
A singular value decomposition of a matrix AA is as follows: A=
| .5 | .5 | .5 | .5 |
| .5 | .5 | -.5 | -.5 |
| .5 | -.5 | -.5 | .5 |
| .5 | -.5 | .5 | -.5 |
| 20 | 0 |
| 0 | 10 |
| 0 | 0 |
| 0 | 0 |
| .8 | .6 |
| .6 | -.8 |
1. Find the closest (with respect to the Frobenius norm) matrix of rank 1 to A.
2. Find the Frobenius norm of ||AA1||F=
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