A sinusoidally oscillating current () with an amplitude of 2.55A and a frequency of 463cycles per second is carried by a long, straight wire. A rectangular loop of copper wire with dimensions =9.18cm by =4.13cm is located =10.2cm from the straight wire, and is coplanar withit.

Calculate the average power avg dissipated by the loop if its resistance is44.3.

Answer rating: 100% (QA)

To calculate the average power dissipated by the loop we can use the formula Pavg 1T 0 to T It2 R dt ... View the full answer