A solid disk starts off with a linear speed of $1\mathrm{.}5$ m$/$s$,$ then it rolls $4\mathrm{.}5$ meters down a hill. It approaches and then rolls up a second hill. Assume the disk rolls without slipping the entire time, and that mechanical energy is conserved. Recall that the moment of inertia of solid disk rotating about its center is given by $.($a$)$ What is the speed of the disk $($in m$/$s$)$ when it gets to the bottom of the hill? $($b$)$ How high up the second hill $($in meters$)$ will it go before rolling back down?