A solid titanium alloy [G = 114 GPa] shaft that is 720 mm long will be...

      

Transcribed Image Text:

A solid titanium alloy [G = 114 GPa] shaft that is 720 mm long will be subjected to a pure torque of T = 155 N . m. Determine the minimum diameter required if the shear stress must not exceed 150 MPa and the angle of twist must not exceed 7°. Report both the maximum shear stress r and the angle of twist p at this minimum diameter. v Part 1 x Incorrect. Consider the elastic torsion formula. The maximum shear stress occurs at the radial location p = (d/2), where d is the shaft diameter. The polar moment of inertia is also a function of d. Find the value of d for which the maximum shear stress in the shaft equals 150 MPa. Based only on the requirement that the shear stress must not exceed 150 MPa, what is the minimum diameter of the shaft? d, 16.1763 mm the tolerance is +/-2% Based only on the requirement that the angle of twist must not exceed 7°, what is the minimum diameter of the shaft? %3D mm Part 3 X Incorrect. The minimum diameter that meets the maximum shear stress specification has been determined and the minimum diameter that meets the maximum angle of twist specification has been determined. Enter the larger of these two. Determine the minimum diameter required. dmin ='l16.1763 mm the tolerance is +/-2% Determine the polar moment of inertia corresponding to the minimum diameter for the shaft. J = mm* 4 the tolerance is +/-2% Part 5 Determine the maximum shear stress at the minimum diameter. Tmax = MPa the tolerance is +/-2% Part 6 Determine the angle of twist in the shaft at the minimum diameter. Enter your answer in degrees. the tolerance is +/-2% A solid titanium alloy [G = 114 GPa] shaft that is 720 mm long will be subjected to a pure torque of T = 155 N . m. Determine the minimum diameter required if the shear stress must not exceed 150 MPa and the angle of twist must not exceed 7°. Report both the maximum shear stress r and the angle of twist p at this minimum diameter. v Part 1 x Incorrect. Consider the elastic torsion formula. The maximum shear stress occurs at the radial location p = (d/2), where d is the shaft diameter. The polar moment of inertia is also a function of d. Find the value of d for which the maximum shear stress in the shaft equals 150 MPa. Based only on the requirement that the shear stress must not exceed 150 MPa, what is the minimum diameter of the shaft? d, 16.1763 mm the tolerance is +/-2% Based only on the requirement that the angle of twist must not exceed 7°, what is the minimum diameter of the shaft? %3D mm Part 3 X Incorrect. The minimum diameter that meets the maximum shear stress specification has been determined and the minimum diameter that meets the maximum angle of twist specification has been determined. Enter the larger of these two. Determine the minimum diameter required. dmin ='l16.1763 mm the tolerance is +/-2% Determine the polar moment of inertia corresponding to the minimum diameter for the shaft. J = mm* 4 the tolerance is +/-2% Part 5 Determine the maximum shear stress at the minimum diameter. Tmax = MPa the tolerance is +/-2% Part 6 Determine the angle of twist in the shaft at the minimum diameter. Enter your answer in degrees. the tolerance is +/-2%

Answer rating: 100% (QA)

AT I55 N m 720mm Emax I SO mpa ... View the full answer