A solution is prepared that is initially $0\mathrm{.}48M$ in benzoic acid $(H{C}_6{H}_{5}C{O}_2)$ and $0\mathrm{.}33M$ in sodium benzoate $(Na{C}_6{H}_{5}C{O}_2).$ Complete the reaction table below, so that you could use it to calculate the $pH$ of this solution.

Use $x$ to stand for the unknown change in $H_3{O}^{+}.$ You can leave out the $M$ symbol for molarity.

$\backslash$table$[[$initial$,,,$