A split$-$ring clamp$-$type shaft is shown in the figure. The screw must resist an axial load $F_x$ of $1,700$ lbf$.$ Using a design factor of $n_d=3$ and a coefficient of friction of $0\mathrm{.}12,$ specify an SAE grade $5$ cap screw using fine threads. Use the relationship

$F_x=\frac{2f(T)}{Kd}$

In this equation, $F_x$ is the axial force in the screw, $f$ is the coefficient of friction, $T$ is the tightening torque, $K$ is the torque factor, and $d$ is the nominal diameter of the screw. Assume it is desirable that the axial load is equal to the preload for a reusable screw. What wrench torque should be used if a lubricated screw is used? Round to the nearest $25$ in$-$lbf$.$ Verify the design factor still exceeds $3$ with the modified torque.

The torque rounded to the nearest $25$ in $-$Ibf is $$

Ibf.in$.$

The factor of safety is $.($Round the final answer torthree decimal places.$)$

The nominal diameter is $$ in$.($Round the final answer to three decimal places.$)$