Question: A spring with a 5-kg mass and a damping constant 12 can be held stretched 1.5 meters beyond its natural length by a force of

A spring with a 5-kg mass and a damping constant 12 can be held stretched 1.5 meters beyond its natural length by a force of 6 newtons. Suppose the spring is stretched 3 meters beyond its natural length and then released with zero velocity. In the notation of the text, what is the value(^2)-4mk?

Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t of the formc1e^()+c2e^(t)

where = ?(the smaller of the two)

=?(the larger of the two)

c1=? c2=?

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