Question: A string stretched out between two fixed posts is set vibrating by a mechanical oscillator attached to one end. (1) The string is oscillating in

A string stretched out between two fixed posts is set vibrating by a mechanical oscillator attached to one end. (1) The string is oscillating in a standing wave with 5 loops, then sketch the standing wave and label all nodes (N) andantinodes (A). (2) The frequency illustrated in #1 249 Hz. Calculate the frequency you'd have to set the oscillator to in order to add one more loop to the standing wave. (3) The string is L = 3.08 m long. Calculate the wavelength of the standing wave you sketched in #1. (4) Calculate the speed v of the waves on the string. (5) The string's mass is m = 4.79 g. Calculate the magnitude of the string's tension. Watch units! (6) In #2 you calculated the oscillator frequency that would add one more loop to the standing wave. An alternative way to add one more loop is to adjust the tension of the string while keeping the oscillator set to itscurrent frequency, the one chosen in #2. This requires reducing the wavelength so that another loop can be squeezed in between the posts. Since = v/f,the wave speed must be decreased to reduce the wavelength. Should you increase or decrease the string tension,then, to add another loop to the standing wave? Explain in 1-2 sentences. (7) Calculate the tension that will add one more loop to the standing wave at the frequency chosen in #2. The string's linear density = m/L remains constant.

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