Question: A tapered bar with circular cross section is fixed at x 0 and, an axial force of 0.3x10 N is applied at the other

A tapered bar with circular cross section is fixed at x 0

A tapered bar with circular cross section is fixed at x 0 and, an axial force of 0.3x10 N is applied at the other end. The length of the bar (L) is 0.3 m, and the radius varies as r(x) = 0.03 - 0.07r. where r and x are in meters. Use three equal- length finite elements to determine the displacements, axial force resultants and support reactions. Compare your FE solutions with the exact solution by plotting u vs. x and P(element force) vs. x. Use E= 100 Pa. 0.3x10 N 0.3 m

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