Question: a). The coefficients and intercept given in part a are for the linear equation in the form 0 = 0 + 11 + 22. Rearrange
a). The coefficients and intercept given in part a are for the linear equation in the form 0 = 0 + 11 + 22. Rearrange the formula (using algebra) such that it is in the form 2 = + 1.
0= W0 + W1X1 +W2X2
-W2X2 =W0+W1X1
X2 =(-W0/W2) (W1/W2) X1
Let m = - W0/W2 and b = W1/W2
X2 = m + b(X1) where m= -W0/W2 and b = -W1/W2
Create a scatter plot of the two variables TotExp and Totlns . Treat the weak and strong records as two separate series/sets of data in the plot.
| Obs | Financial Condition | TotCap/Assets | TotExp/Assets | TotLns&Lses/Assets |
| 1 | 1 | 9.7 | 0.12 | 0.65 |
| 2 | 1 | 1 | 0.11 | 0.62 |
| 3 | 1 | 6.9 | 0.09 | 1.02 |
| 4 | 1 | 5.8 | 0.1 | 0.67 |
| 5 | 1 | 4.3 | 0.11 | 0.69 |
| 6 | 1 | 9.1 | 0.13 | 0.74 |
| 7 | 1 | 11.9 | 0.1 | 0.79 |
| 8 | 1 | 8.1 | 0.13 | 0.63 |
| 9 | 1 | 9.3 | 0.16 | 0.72 |
| 10 | 1 | 1.1 | 0.16 | 0.57 |
| 11 | 0 | 11.1 | 0.08 | 0.43 |
| 12 | 0 | 20.5 | 0.12 | 0.8 |
| 13 | 0 | 9.8 | 0.07 | 0.69 |
| 14 | 0 | 7.9 | 0.08 | 0.53 |
| 15 | 0 | 9.6 | 0.09 | 0.73 |
| 16 | 0 | 12.5 | 0.09 | 0.3 |
| 17 | 0 | 18.3 | 0.08 | 0.49 |
| 18 | 0 | 7.2 | 0.11 | 0.55 |
| 19 | 0 | 14 | 0.08 | 0.44 |
| 20 | 0 | 8.3 | 0.08 | 0.51 |
Add the line you solved for in part (a) to the scatter plot. (You will need to create a column of values for TotExp/Assets, e.g. [0, .05, .10, .15, .20], then calculate the value from the line in part (a) for each value. Suppose a bank has TotExp/Assets = 0.12 and TotLns&Lses/Assets = 0.48. Would this bank be classified as weak or strong?
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