Question: a). The coefficients and intercept given in part a are for the linear equation in the form 0 = 0 + 11 + 22. Rearrange

a). The coefficients and intercept given in part a are for the linear equation in the form 0 = 0 + 11 + 22. Rearrange the formula (using algebra) such that it is in the form 2 = + 1.

0= W0 + W1X1 +W2X2

-W2X2 =W0+W1X1

X2 =(-W0/W2) (W1/W2) X1

Let m = - W0/W2 and b = W1/W2

X2 = m + b(X1) where m= -W0/W2 and b = -W1/W2

Create a scatter plot of the two variables TotExp and Totlns . Treat the weak and strong records as two separate series/sets of data in the plot.

Obs Financial Condition TotCap/Assets TotExp/Assets TotLns&Lses/Assets
1 1 9.7 0.12 0.65
2 1 1 0.11 0.62
3 1 6.9 0.09 1.02
4 1 5.8 0.1 0.67
5 1 4.3 0.11 0.69
6 1 9.1 0.13 0.74
7 1 11.9 0.1 0.79
8 1 8.1 0.13 0.63
9 1 9.3 0.16 0.72
10 1 1.1 0.16 0.57
11 0 11.1 0.08 0.43
12 0 20.5 0.12 0.8
13 0 9.8 0.07 0.69
14 0 7.9 0.08 0.53
15 0 9.6 0.09 0.73
16 0 12.5 0.09 0.3
17 0 18.3 0.08 0.49
18 0 7.2 0.11 0.55
19 0 14 0.08 0.44
20 0 8.3 0.08 0.51

Add the line you solved for in part (a) to the scatter plot. (You will need to create a column of values for TotExp/Assets, e.g. [0, .05, .10, .15, .20], then calculate the value from the line in part (a) for each value. Suppose a bank has TotExp/Assets = 0.12 and TotLns&Lses/Assets = 0.48. Would this bank be classified as weak or strong?

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