A uniform disk $(I_0=\frac{1}{2}m{R}^2)$ of mass $m$ and radius $R$ is suspended from a point on its rim. The moment of inertia of the disk about an axis perpendicular to the disk through the pivot point is

$\frac{1}{2}m{R}^2.$

$m{R}^2.$

$1\mathrm{.}5m{R}^2$

$2m{R}^2.$

$2m\frac{R^2}{3}$