A uniform disk with radius $0\mathrm{.}600$ mm and mass $30\mathrm{.}0$ kgkg rotates in a horizontal plane on a frictionless vertical axle that passes through the center of the disk. The angle through which the disk has turned varies with time according to $($t$)=(1\mathrm{.}10$rad$/$s$)$t$+(6\mathrm{.}30$rad$/$s$2)$t$2$$($t$)=(1\mathrm{.}10$rad$/$s$)$t$+(6\mathrm{.}30$rad$/$s$2)$t$2.$

Part A

What is the resultant linear acceleration of a point on the rim of the disk at the instant when the disk has turned through $0\mathrm{.}100$ revrev?

Express your answer with the appropriate units.