A uniform disk with radius $0\mathrm{.}800m$ and mass $30\mathrm{.}0kg$ rotates in a horizontal plane on a frictionless vertical axle that passes through the center of the disk. The angle through which the disk has turned varies with time according to $(t)=(1\mathrm{.}10ra\frac{d}{s})t+(6\mathrm{.}30ra\frac{d}{s^2})t^2.$

Part A

What is the resultant linear acceleration of a point on the rim of the disk at the instant when the disk has turned through $0\mathrm{.}100$rev $?$

Express your answer with the appropriate units.

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