A$.$ Unit Conversion Assuming that all concentrations are in aqueous solution $($density$=1\mathrm{.}0$ g$/$mL$),$

answer the following.

$,2\mathrm{.}4{10}^{-3}n\frac{g}{L}$ of NaCl$-=?m\frac{g}{k}g$

$6\mathrm{.}0{10}^3\frac{g}{L}$ of $NaC{l}_{-}=?n\frac{g}{m}L$

$0\mathrm{.}40{10}^{-3}n\frac{g}{L}=,\frac{g}{m}L$

$,0\mathrm{.}80{10}^{-2}ppm=,\frac{g}{L}$

$,0\mathrm{.}50mo\frac{l}{L}$ of NaCl$(58\mathrm{.}5\frac{g}{m}ol)=,\frac{g}{m}L$

Find the concentration of $C{a}^{2+}(40\frac{g}{m}$ole$)$ expressed as ppm for a solution containing $0\mathrm{.}020M$ of

$CaC{O}_3(100\frac{g}{m}$ole$)$

B$.$ Preparation of Standard Solution from Stock Solution.

Having $5\mathrm{.}0M$ of stock $HCl$ solution, what is the initial volume of this solution needed to prepare

$25\mathrm{.}0mL$ of $2\mathrm{.}0MHCl?$

$8\mathrm{.}0mL$ of stock solution is transferred into $50\mathrm{.}0mL$ flask and diluted into the mark. If the

concentration of the prepared $50\mathrm{.}0mL$ solution is $0\mathrm{.}20M,$ what is the concentration of stock

solution?