A vase can be modeled using * 2 ( 1 - 4 ) 2 = 1 and the x-axis, for 0 s y s 20, where the measurements are in 6.25 42.25 inches. Using the graph, what is the distance across the base of the vase, and how does it relate to the hyperbola? (2 points) 2.25 inches; length of the transverse axis 2.94 inches; distance between the intercepts O 4.50 inches; length of the transverse axis O 5.87 inches; distance between the x-intercepts