A velocity selector uses an electric field E$=(2\mathrm{.}80104$N$/$C$)$i$^$E$=(2\mathrm{.}80104$N$/$C$)$i$^$ and a magnetic field B$=(0\mathrm{.}0450$T$)$k$^$B$=(0\mathrm{.}0450$T$)$k$^.$ What particle speed will yield zero deflection?

Express your answer with the appropriate units.

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Part H

In what direction should a positively charged particle travel through these fields to have zero deflection?

It should travel in the $-$yy$-$direction.It should travel in the $+$yy$-$direction.It should travel in the $-$xx$-$direction.It should travel in the $-$zz$-$direction.It should travel in the $+$xx$-$direction.

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Part I

A positively charged particle travels through these fields with the speed you found in part G and the direction you found in part H$,$ but the magnetic$-$field magnitude is now greater than $0\mathrm{.}0450$ TT$.$ In what direction will the particle initially be deflected?

It would deflect in the $+$xx$-$direction.It would deflect in the $-$zz$-$direction.It would deflect in the $-$yy$-$direction.It would deflect in the $-$xx$-$direction.