. Question 4 E 2 pts '0 1 6) Details A bunch of crazy robots have assembled a sphere of charge with a radius R: 5 m. Their sphere has a non-uniform charge density given by p(r)=ar5 (rsR) where a=3.4 nC-m'8. The robots want to use Gauss's Law to figure out the electric field due to the sphere, and they remember that they'll need to know the charge enclosed by their imaginary Gaussian surface. Because they have a non- uniform charge, they can't simply multiply the p by volume, they will need to take the following integral with the limits going from zero to the radius of the Gaussian surface: Q=fpdV=4pifpr2dr First the robots consider a Gaussian surface inside of their charged sphere with a radius of 2. How much charge is enclosed? nC What is the electric field at the Gaussian surface? N/C Of course, the robots also want to know what is going on outside of the charged sphere, so they consider a Gaussian surface of radius 9 m. How much charge is enclosed by this Gaussian surface? nC What is the electric field at the larger Gaussian surface? N/C Check