Question: A. We wish to send a 150,000 byte message over a network with four hops, each of length 20km and running at 100 Mb/s. What

A. We wish to send a 150,000 byte message over a network with four hops, each of length 20km and running at 100 Mb/s. What is the end-to-end delay of the message? Use speed of light in copper = c = 2 * 10^8 m/s, and round your answer to the nearest integer millisecond.

B. We wish to send a message of size 150,000 bytes over the network. There are four hops, each of length 20km and running at 100 Mb/s. However, before sending we split the message into 1500 byte packets. What is the end-to-end delay of the message? Use speed of light in copper = c = 2 * 10^8 m/s, and round your answer to the nearest integer millisecond.

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