A well 12 inches (1 ft) in diameter is drilled into an unconfined aquifer. Head at...
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A well 12 inches (1 ft) in diameter is drilled into an unconfined aquifer. Head at location 500 ft away from the well is 100 ft above the aquifer base. The aquifer is homogeneous with conductivity k=10 ft/day. The head at location r=100 ft from the center of the well equals 95 feet. • Calculate the flow Q out of the well. Calculate head at the well (at r=0.5ft). • If water needs to be lifted 40 feet from the well surface up, estimate the power of the pump that is lifting the water. ground surface k=10 ft/day D=12 100 ft 95 ft 500 ft 100 ft A well 12 inches (1 ft) in diameter is drilled into an unconfined aquifer. Head at location 500 ft away from the well is 100 ft above the aquifer base. The aquifer is homogeneous with conductivity k=10 ft/day. The head at location r=100 ft from the center of the well equals 95 feet. • Calculate the flow Q out of the well. Calculate head at the well (at r=0.5ft). • If water needs to be lifted 40 feet from the well surface up, estimate the power of the pump that is lifting the water. ground surface k=10 ft/day D=12 100 ft 95 ft 500 ft 100 ft
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Answer rating: 100% (QA)
SOLUTION To calculate the flow rate Q out of the well we can use Darcys Law which states Q k A dhdr ... View the full answer
Related Book For
Fundamentals Of Hydraulic Engineering Systems
ISBN: 978-0136016380
4th Edition
Authors: Robert J. Houghtalen, A. Osman H. Akan, Ned H. C. Hwang
Posted Date:
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