A Wendy's manager performed a study to determine the probability distribution for the number of people waiting in line during lunch The results are as follows No Waiting Probability 0 05 1 20 2 35 3 20 4 20 (a) What is the mean number of people waiting in line (b) What is the standard deviation for the number of people waiting in line (c) What is the probability that there is one person waiting in line given at least one person waiting in line

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Question: A Wendy's manager performed a study to determine the probability distribution for the number of people waiting in line during lunch. The results are as

A Wendy's manager performed a study to determine the probability distribution for the number of people waiting in line during lunch. The results are as follows:

No. Waiting	Probability
0	.05
1	.20
2	.35
3	.20
4	.20

(a) What is the mean number of people waiting in line?

(b) What is the standard deviation for the number of people waiting in line?

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