Question: A wet solid is to be dried in a tray dryer under steady-state conditions from a free moisture content of X 1 = 0.40 kg

A wet solid is to be dried in a tray dryer under steady-state conditions from a free moisture content of X 1 = 0.40 kg H 2 O/kg dry solid to X 2 = 0.02 kg H 2 O/kg dry solid. The dry solid weight is 99.8 kg dry solid and the top surface area for drying is 4.645m 2 . Calculate the time for drying using a straight line through the origin for drying rate in the falling-rate period.


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To solve this problem we need to calculate the drying time using the data provided The drying process youre referring to involves two primary stages t... View full answer

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