Question: a) Why does the code below print 1 ? What happens with ++ #include main(){ int a=1,b=2; b=a++; printf(%d ,b++; } b) please explain the
a) Why does the code below print 1 ? What happens with ++
#include
main(){
int a=1,b=2;
b=a++;
printf("%d ",b++;
}
b) please explain the output of the segment below. Having trouble with compiling.
What would be the output from the code segment below?
switch ( 'b' ) {
case 'a':
printf("a ");
case 'b': printf("b ");
default: printf("default");
}
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