A metal with a lattice constant of a = 2.87 forms a grain boundary in...

 

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A metal with a lattice constant of a = 2.87 Å forms a grain boundary in a tilt angle of -5°, the bond strength of the metal is 75 kJ/mol, deduce the surface energy of the grain boundary. Assuming the distance between dislocations is D as shown, Burgers vector is 2.5nm, calculate the dislocation density along the boundary per 1cm long. Grain 1 Grain Boundary Grain 2 Unit length PROD cos a broken bonds sin/a broken bonds D A metal with a lattice constant of a = 2.87 Å forms a grain boundary in a tilt angle of -5°, the bond strength of the metal is 75 kJ/mol, deduce the surface energy of the grain boundary. Assuming the distance between dislocations is D as shown, Burgers vector is 2.5nm, calculate the dislocation density along the boundary per 1cm long. Grain 1 Grain Boundary Grain 2 Unit length PROD cos a broken bonds sin/a broken bonds D

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To calculate the surface energy of the grain boundary we can use the following equation gamma G b 2 ... View the full answer