a2+ 6 2 = C2 7.3 HW 1 . * = 4tan (0 ) a = 4 dx = 4 see 2 x Sum of squares : ( ase co ) ? = 9 2 + (atan 8 ) 2 ( itand ) . 4 seco do * Ullotan 26 + 16 ( 4 tano ) 2 + 16 - J 16 ( tan ? e + 1 ) ( 4 tano ) 16 5sec 20 *seek do 4 sect = 4 seco ( 4 tan @ ) ( sec 0 ) do = 64 ( ( tan' 0 ) ( sec B > de = 64 ( tane ) ( tan > (tan @ ) sec 01 do v = Sec ca) du = sec e tan ads JX 2 + 16 X - 41 tano du = 64 \\ sec-D - 1 du 4 = 141 tang - 0 7 + c X = 4 tan @ * = tano = ads opp = 64 [tano- 0] +c arctan ( 4 ) = 0 = 64 5 4 - arctan ( #) + cEvaluate the integral using the indicated trigonometric substitution. (Use C for the constant of integration.) [ dx, x = 4 tan(-9) 4( 3': arctan( 1(1)) +C X