Question: (Abbott, Exercise 1.4.1) Recall that I stands for the set of irrational numbers. (a) Show that if a,b e Q then a +b and ab

(Abbott, Exercise 1.4.1) Recall that I stands for

(Abbott, Exercise 1.4.1) Recall that I stands for the set of irrational numbers. (a) Show that if a,b e Q then a +b and ab are elements of Q as well. (b) Show that if a E Q and tEI, then a +te I and at E I as long as a # 0. (c) Part (a) can be summarized by saying that Q is closed under addition and multiplication. Is I closed under addition and multiplication? Given two irrational numbers s and t, what can we say about s +t and st

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