Question: ABCD is inscribed in circle O. m COD = 70. AOD is the diameter, PB is tangent to circle O at B. PCOE is a

ABCD is inscribed in circle O. m COD = 70. AOD is the diameter, PB is tangent to circle O at B. PCOE is a secant and mBA = mCD. Find m BCm PBCm Am BPEm AFE

ABCD is inscribed in circle O. m COD = 70. AOD is
36 P Find : B a. m BC C b. m/ PBC # F A 70 D C. ML A O do m/ BDE = F e. my AFE

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