Accept two numbers and find their sum and difference. If the sum is more than the difference, display the sum otherwise display the difference. Odd & Even Number program using loop (repeat 5 time)

#include using namespace std;

int main() { int n; for(int i = 0;i < 5;i++) { cin >> n; if(n%2 == 1) cout << "Odd "; else cout << "Even "; } return 0; }

-------------using C++-------------------

Modify the program to use these functions void informUser(); void checkSum(int); int add(int,int);//return A VALUE void enterNumbers(int&,int&);