Question: According to distribution, [C & (T v A)] is equivalent to: [(C v T) & (C v A)] [(C & A) v (T & A)]
According to distribution, [C & (T v A)] is equivalent to: [(C v T) & (C v A)] [(C & A) v (T & A)] [(C & T) v (C & A)] [(C v A) & (T v A)]
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