Blake wonders why adding capacitors in parallel results in an equivalent capacitance that is the sum of the individual capacitances. What is Kylie's response? "When capacitors are in parallel, the charge on each is equal, and so the capacitance must also be equal for a given voltage, from C = Q V . Therefore, the equivalent capacitance is the sum of the individual capacitances." "The capacitance of a single parallel-plate capacitor is proportional to the area of the plates, from C = 0A d . If we have two parallel-plate capacitors, and we combine them in parallel and bring them very close together side by side, we have produced a single capacitor with plates of area A1 + A2, which means Cnew = C1 + C2. Extending this idea for n capacitors, we get Ceq is the sum of the n individual capacitances." "The capacitance of a single parallel-plate capacitor is proportional to the area of the plates, from C = 0Ad. If we have two parallel-plate capacitors, and we combine them in parallel and bring them very close together side by side, we have produced a single capacitor with plates of area A1 + A2, which means Cnew =