Question: According to the information from problem 2 , calculate the mean free path of each nuclide with the corresponding energies, given the densities of 92235U

According to the information from problem 2 , calculate the mean

According to the information from problem 2 , calculate the mean free path of each nuclide with the corresponding energies, given the densities of 92235U are 19.1g/cm3 and 8.65g/cm3. (1.5 points) a. 92235U with energy of 1eV,12.38eV, and 106eV b. 48113Cd with energy of 1eV,0.1eV, and 107eV c. Explain why the m.f.p of 92235U with 12.38eV incident neutron energy is smaller than 1eV

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To calculate the mean free path lambda of each nuclide we need to use the formula lambda frac1nsigma ... View full answer

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