Activity:

Part 1:

Data has been gathered on the different possible materials which are being selected for the support beams and columns that the construction company you work at is interested in using.From this data generate a short report showing the effect that the scientific method has on different test procedures which have been used to provide us the information in the table below and represent the information given in an appropriate graphical format. The report also needs to include an explanation of prefix notation and SI units when converting the values from the given to the standard, explaining to the reader why we use SI units, commenting on their importance. Below is the task given to you directly by your manager.

'A construction company is deciding on what material to make their horizontal and vertical visible load bearing supports from, can you represent the data in both tables below graphically to aid in their decision making. Describe the SI Units involved. A group of 100 members of the public have answered a survey that is looking into their opinions of the varying materials used, this is represented on the second table below.'

	Young's Modulus	Ultimate Tensile Strength	Yield Strength
Mild Steel	205GPa	394,720,000Pa	294.74MPa
Stainless Steel	180,000,000,000Pa	0.860GPa	502,000KPa
Aluminium	69,000MPa	110,000KPa	0.095GPa
Titanium	115GPa	1.031GPa	880,000,000Pa
Wrought Iron	193,100,000KPa	303MPa	190,000KPa
Zinc	83,000MPa	246,000KPa	126MPa
Tin	47,000,000,000Pa	200,000,000Pa	54,000,000Pa
Bronze	108GPa	241.31MPa	0.1379GPa
Gold	74,000MPa	220,000KPa	205,000Kpa
Copper	117,000,000KPa	220,000,000Pa	70MPa

	Dislike	Somewhat Dislike	Neutral	Somewhat Like	Like
Mild Steel	8	12	30	45	5
Stainless Steel	2	8	26	43	21
Aluminium	4	22	18	38	18
Titanium	6	15	20	28	31
Wrought Iron	38	29	17	12	4
Zinc	7	26	33	29	5
Tin	22	24	31	14	9
Bronze	7	13	15	16	49
Gold	4	9	18	21	48
Copper	1	7	15	32	45

Part 2:

Calculate the reaction forces of two supports acting on a simply supported beam, one on either side. The beam has an evenly distributed force going down of 6 KN/m acting from on top of support A spanning for 0.75m, at 1m there is a downwards force of 8KN, another 1.6m along there is an upwards force of 4KN with the final force acting downwards with 2 KN of force and placing 80cm away from the 4KN force. The total length of the beam is 4.5m

\f8KN 2KN 6KN/m 1.6m K 0. 75 m 80 cm Im 4KN R B K 4.5 M