After running solver, we got the sensitivity analysis table as following.

Table $1$: Sensitivity Analysis for Tropicsun

$\backslash$table$[[\frac{\text{C}\text{o}\text{l}\text{l}}{\text{\$}D\text{\$}11},$Name,$\backslash$table$[[$Final$],[$Value$]],\backslash$table$[[$Shadow$],[$Price$]],\backslash$table$[[$Constraint$],[$R$.$H$.$ Side$]],\backslash$table$[[$opicsin$],[$Allowable$],[$Increase$]],\backslash$table$[[$Allowable$],[$Decrease$]]],[,$Mt$.$ Dora,$275000,48,275000,50000,75000],[,$Eustis,$400000,30,400000,50000,250000],[\frac{\text{\$}D\text{\$}13}{\text{\$}D\text{\$}14},$Clerment,$300000,20,300000,50000,300000],[\frac{\text{\$}0\text{\$}14}{\text{\$}0\text{\$}15},$Ocala,$200000,-27,200000,75000,50000],[$$$D$$$15,$Orlando,$550000,0,600000,1E+30,50000],[$$$D$$$16,$Leesburg,$225000,-8,225000,250000,50000]]$

Tropicsun has an options to improve their infrastructure. The first option is that increase a capacity of one plant by $50,000$ bushels. But it will costs $$200,000.$ Which plant should Tropicsun to choose for capacity increase, or no plant to invest at all, if the transportation cost is $$1$ per bushel$-$mile? Justify your conclusion.

Since the shadow price of Ocala capacity is $-27($it means if we have one more uni of capacity, our objective function value will go down by $$27.$ This means one mor unit of capacity is $$27$ saving. And the allowable increase is $75,000$ which is greate than $50,000.$ We can save $50,000$$$27.$ Even though we have to pay $$200,000$ for th capacity increment, we can save more than $$200,000$ in transportation cost. We ca save by choosing Leesburg plant. However, the saving would be smaller than that the Ocala case.