Air is cooled as it flows without friction at a rate of 0.05 kg/s in a duct.

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Air is cooled as it flows without friction at a rate of 0.05 kg/s in a duct. At point 1 the conditions are M1 = 0.5, T1 = 500C, and p1 =500 kPa (abs). Downstream, at point 2 , the conditions are M2 = 0.2, T2= 218.57C, and p2 =639.2 kPa (abs). (Four significant figures are given to minimize roundoff errors.) Compare the stagnation temperatures at points 1 and 2 , and explain the result. Compute the rate of cooling. Compute the stagnation pressures at points 1 and 2 . Should this process be isentropic or not? Justify your answer by computing the change in entropy between points 1 and 2 . Plot static and stagnation state points on a Ts diagram.

Posted Date: Sep 24, 2021 08:04 AM

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Air is cooled as it flows without friction at a rate of 0.05 kg/s in a duct.

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a Find the stagnation temperature at section 1 1 2 141 14 X052 500 273 2 Tn 81165K ... View the full answer

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