also if you could provide the lcl that would be great

Homework: Homework 7: Quality core: 0 of 1 pt 7 of 15 (6 complete) HW Score: 36 "roblem 6s.7 Refer to Table 56.1. Fadors for Computing Control Chart Limits sime for this problem Auto pistons at Wimming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled From sample sizes of 10 pistons produced each day, the mean this dames have been as follows Range R (mm) What is the value of - 154.36 mm (round your response to two decimal places) by What is the wall R = 452 mm (round your response to two decimal places) Enter your answer in the answer box and then chok Check Answer 1 1 emang part Type here to search UUICI UJ. What is the value of R? R= 4.52 mm (round your response to two decimal places). =) What are the UCL and LCL using 3-sigma? Upper Control Limit (UCL) = 155.75 mm (round your response to two decimal places). Lower Control Limit (LCL:) = 152.96 mm (round your response to two decimal places). d) What are the UCLR and LCLR using 3-sigma? Upper Control Limit (UCLR)8.03 mm (round your response to two decimal places). Lower Control Limit (LCL) 1.008 mm (round your response to two decimal places). e) If the true diameter mean should be 155 mm and you want this as your center nominal) line, what are the new UCL, and LCL:7 Upper Control Limit(UCL) mm (round your response to two decimal places) Enter your answer in the answer box and then click Check Answer 1 part remaining Clear All Type here to search DOLL