An electron moves through a uniform magnetic field given by B = Bxi+(2.12 Bx) j. At a particular instant, the electron has velocity o = (1.89/+4.70 j) m/s and the magnetic force acting on it is (3.82 x 10-19) k N. Find Bx- Number Units T T-m eTextbook and Media T/5 J/T Wb GO Tutorial Wb/m Save for Later Attempts: 0 of 3 used Submit AnswerAn electric field of 1.61 kV/m and a magnetic field of 0.454 T act on a moving electron to produce no net force. If the fields are perpendicular to each other, what is the electron's speed? Number Units This answer has no units "(degrees) eTextbook and Media m kg S Save for Later Attempts: 0 of 3 used Submit Answer m/s m/s^ 2 N J W N/m kg.m/s or N-s N/m^2 or Pa kg/m^3 m/5^3 timesIn the figure, a particle moves along a circle in a region of uniform magnetic field of magnitude B = 3.2 mT. The particle is either a proton or an electron (you must decide which). It experiences a magnetic force of magnitude 3.3 x 10-15 N. What are (a) the particle's speed, (b) the radius of the circle, and (c) the period of the motion? OB (a) Number Units This answer has no units "(degrees) (b) Number Units m kg S m/s (c) Number Units m/s^ 2 N J W eTextbook and Media N/m kg-m/s or N's N/m^2 or Pa GO Tutorial kg/m^ 3 m/s^3 times Save for Later Attempts: 0 of 3 used Submit