An engineer is choosing between three different alternatives for a machine component he needs to complete his biorefinery. He summarized the pertinent information about these alternatives in the tables below. Assume a study period of 8 years

Alternative	Investment Cost	Salvage Value	Useful Life	Depreciation Method
A	100000	25000	8	Sum of the Years
B	70000	20000	4	Straight Line
C	76000	5000	6	Declining Balance

The table below shows the projected net cash flows for each of the alternatives.

EOY	Alternative A	Alternative B	Alternative C
1	30000	-20000	30000
2	40000	40000	30000
3	50000	50000	30000
4	60000	8000	30000
5	70000	-	30000
6	80000	-	30000
7	90000	-	-
8	100000	-	-

Find the Future Worth of Alternative B (MARR of 12.5%), and the Annual Worth of A, B, and C (MARR of 8%).

Answers should be:

FW:

B = -14903.22

AW:

B = 1825.86

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