An engineer working in an electronics lab connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 260 V. Assume a plate separation of d=1.61 cm and a plate area of A 25.0 cm. When the battery is removed, the capacitor is plunged into a container of distilled water. Assume distilled water is an insulator with a dielectric constant of 80.0. (a) Calculate the charge on the plates (in pc) before and after the capacitor is submerged. (Enter the magnitudes.) before Q = after Qf pc PC (b) Determine the capacitance (in F) and potential difference (in V) after immersion. C AV = (c) Determine the change in energy (in n3) of the capacitor. AU- nJ (d) What If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the 260 V potential difference. Calculate the charge on the plates (in pc) before and after the capacitor is submerged. (Enter the magnitudes.) before Q = after Q = PC pc Determine the capacitance (in F) and potential difference (in V) after immersion. C = F AV,- Determine the change in energy (in n]) of the capacitor. AU- nJ