An experimenter runs a EVOP program for two factors A and B, using a 2² design with a center point. Assume that the aim is to maximize the response. The average

\f7.2.4 Addition of center points to 2 design ss= Contrast 2 Exercise 6. A unreplicated 22 design is performed with 5 center points. Responses 12k at the four factorial points are (1) = 1, a = 2, b = 3, ab = 4 and the responses at + 6=3 the 5 center points are 1, 2, 3, 4 and 5. Construct the ANOVA table. X ab= 4 B X YE = 172+ 3+4 = 25, GC = 12+3+4+5 {1 1 2 , 3 4,531 3 * SS= (2+4- 1-3)2 5 (1) = 1 9 = 2 4 =1 SSAB = 1 4- 2-3 4 - A SSB = (3+ 4-1-2)2 = 4 4 SSquad = 4(5 ) ( 2 . 5 - 3 ) 4+5 Source SS MS Fi, 4 P-Values A SSE = (1-33 + ( 2-3) + (3-3)2 B 4 + ( 4- 3) 2 + (5 - 3 ) 2 = 10 AB O AlB AB Quad 5 Error 10 a ab + 1 +1 29