An inverter has to be designed with a resistive load for $V_{DD}=2\mathrm{.}8V$ and $V_L=0\mathrm{.}15V.$ Assume ${?}^{\text{'}}DD=10\mathrm{.}4A($the current supplied by the voltage source $V_{DD},K_n^{\text{'}}=139A{V}^2,$ and $V_{TN}=0\mathrm{.}6V.$

$57$:$33$

Use the given data and calculate the ratio of W$/$L of a transistor to design the inverter. Round off the answer to two decimal places. $(\frac{W}{L}{)}_S=\frac{1}{?}$

Hints:

The pull$-$up resistor $R_D$ can be calculated with the information provided.

$i_D=K_n^{\text{'}}\frac{W}{L}(v_{GS}-V_{TN}-\frac{v_{DS}}{2})v_{DS}$

$K_n^{\text{'}}W$